Magnetic Field due to Current in a Straight Wire

Calculate the magnetic field at the centre of a square loop which carries a current of $1.5 \mathrm{A}$, length of each side is $50 \mathrm{cm}$

Two infinitely long wires carry currents $4 \mathrm{A}$ and $3 \mathrm{A}$ placed along $X$-axis and $Y$-axis respectively. Magnetic field at a point $P\left(0,0, d\right) \mathrm{m}$ will be ________$T$.

Consider a long straight conducting wire. The magnetic field is determined as $B$ at a distance of $5 \mathrm{cm}$ from the wire. The field at $40 \mathrm{cm}$ from the wire would be

$PQ$ and $RS$ are long parallel conductors separated by certain distance. $M$ is the mid-point between them (see the figure). The net magnetic field at $M$ is $B$. Now, the current $4 \mathrm{A}$ is switched off. The field at $M$ now becomes $B$.

In an electric transmission line current is flowing along north direction. On considering earth's magnetic field to be negligible, find the direction of magnetic field above the electric transmission line-

Two parallel, long wires carrying currents $i_1$ and ${\mathrm{i}}_2$ with ${\mathrm{i}}_1>{\mathrm{i}}_2.$ When the currents are in the same direction, the magnetic field at a point midway between the wires is $10\mathrm{}\mathrm{m}\mathrm{T}.$ If the direction of ${\mathrm{i}}_2$ is reserved, the field becomes $30\mathrm{}\mathrm{m}\mathrm{T}.$ Find the ratio ${\mathrm{i}}_1/{\mathrm{i}}_2$.

A straight wire carrying a current of $13 \mathrm{A}$ is bent into a semi-circular arc of radius $2 \mathrm{cm}$ as shown in the figure. The magnetic field is $1.5\times {10}^{-4} \mathrm{T}$ at the centre of the arc, then the magnetic field due to the straight segment is

A long straight wire is carrying current $I$ in $+z$ direction. The $x-y$ plane contains a closed circular loop carrying current $I_2$ and not encircling the straight wire. The force on the loop will be